#A07 · Algebra & Number Theory · Lv.2View in 3D Mind-Map

Arithmetic & Geometric Series Sum

Carl Friedrich Gauss & Archimedes · 1785 CE

Sn=a(1−rn)1−r,S∞=a1−r  (∣r∣<1)S_n = \frac{a(1 - r^n)}{1 - r},\quad S_\infty = \frac{a}{1 - r} \;(|r|<1)
∑k=1nk=n(n+1)2\sum_{k=1}^{n} k = \frac{n(n+1)}{2}

Computes finite and infinite sums of progressions in closed form; for |r| < 1, an infinite geometric series converges to a / (1 - r).

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First term a
Ratio r
Terms n
S8=10(1−0.58)1−0.5=19.922S_{8} = \frac{10(1 - 0.5^{8})}{1 - 0.5} = 19.922
부분합 S_8
19.9219
Infinite Sum S_∞
20.0000
n번째 항 a_n
0.0781
T110.0T25.0T32.5T41.3T50.6T60.3T70.2T80.1

Prerequisite Path (3 STEP)

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Geometric & Intuitive Insight

S_n 에 공비 r을 곱한 r·S_n 을 원래 S_n 에서 빼면 중간 항들이 도미노처럼 모두 지워지고 첫째항 a와 마지막 항 ar^n 만 남습니다(망원급수 원리).

Step-by-Step Derivation

  1. Step 1.1단계: S_n = a + ar + ar² + … + ar^(n-1) 의 양변에 r을 곱합니다 → rS_n = ar + ar² + … + ar^n
  2. Step 2.2단계: 두 식을 빼면 (1 - r)S_n = a - ar^n = a(1 - r^n) 이 됩니다.
  3. Step 3.3단계: r ≠ 1 일 때 S_n = a(1 - r^n)/(1 - r) 이며, |r| < 1 이고 n → ∞ 이면 r^n → 0 이 되어 S_∞ = a/(1 - r)

AI & Coding Real-World Use

Reinforcement Learning discounted return (∑ γ^t R_t) convergence and compound interest valuation

#RL Discounted Return#Quant Finance DCF#Algorithm Loop Analysis
const geoSum = (a: number, r: number, n: number) => a * (1 - Math.pow(r, n)) / (1 - r);

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