一覧へ戻るPeak of Mathematics

オイラーの等式 e^(iπ) + 1 = 0: テイラー級数が指数関数と三角関数を統合する理由

When the compound-growth constant e meets the imaginary unit i, runaway exponential growth transforms into eternal rotation on the unit circle.

eiθ=cos⁡θ+isin⁡θ  ⟹  eiπ+1=0e^{i\theta} = \cos\theta + i\sin\theta \implies e^{i\pi} + 1 = 0
Multiplying by i rotates a complex vector by 90°, turning exponential growth into constant-speed circular motion.
Maclaurin series expansion of e^(iθ) naturally separates into even real powers (cos θ) and odd imaginary powers (i sin θ).
Replaces cumbersome trigonometric identities with simple exponent addition, powering Fourier analysis and quantum mechanics.

1. Alternating Signs in the Maclaurin Expansion

eiθ=∑n=0∞(iθ)nn!=(1−θ22!+θ44!−⋯ )+i(θ−θ33!+θ55!−⋯ )e^{i\theta} = \sum_{n=0}^{\infty} \frac{(i\theta)^n}{n!} = \left(1 - \frac{\theta^2}{2!} + \frac{\theta^4}{4!} - \cdots\right) + i\left(\theta - \frac{\theta^3}{3!} + \frac{\theta^5}{5!} - \cdots\right)

Substituting x = iθ into the Maclaurin series of e^x introduces the 4-cycle of powers of i (1, i, -1, -i), cleanly splitting the infinite sum into the real series for cos θ and the imaginary series for sin θ.

2. Differential Intuition: Why Rotation Instead of Growth?

ddθeiθ=ieiθ  ⟹  Velocity ⊥ Position\frac{d}{d\theta} e^{i\theta} = i e^{i\theta} \implies \text{Velocity } \perp \text{ Position}

In the complex plane, multiplication by i rotates a vector by 90° counterclockwise. Because the derivative d/dθ(e^(iθ)) = i·e^(iθ) is always perpendicular to the position vector, the point traces a unit circle of radius 1.

3. Gateway to Fourier Transform and Modern DSP

f^(ω)=∫−∞∞f(t) e−iωt dt\hat{f}(\omega) = \int_{-\infty}^{\infty} f(t)\,e^{-i\omega t}\,dt

Euler's formula packs both amplitude and phase into a single rotating complex exponential e^(-iωt), enabling Fast Fourier Transform (FFT), Wi-Fi OFDM modulation, and MRI k-space reconstruction.